Yet Another
Very Simple Argument Against Special Relativity
by
Ardeshir
Mehta
Tuesday,
October 9, 2001
Here is yet
another very simple
argument which proves that Special Relativity must
be mathematically flawed,
for the Lorentz transformation equations  which
are absolutely essential
for the Special Theory of Relativity  can give
results which contradict
the Special Theory of Relativity itself.

Let's say
that somewhere out in
deep space, the United Federation of Planets has a
fairly large mothership
of restlength D, and clamped to its hull
there is a fairly small
runabout of restlength d  both ships
facing in the same direction.

Let's say
that when the runabout
is stationary relative to the mothership, the
mothership is exactly ten
times as long as the runabout.

Thus when the
runabout is stationary
relative to the mothership the ratio d/D
is exactly 1/10
 or expressed decimally, 0.1.

Now let's say
the clamps on the
runabout are released, and the runabout fires
its engines, moving away
from the mothership in a straight line, and
eventually reaching a constant
rectilinear velocity v relative to the
mothership.

According to
the Lorentz transformation
equations, the length of the runabout must now be
contracted compared
to what it was in 1. above, namely d.

The
contracted length, d',
must be calculable by the Lorentz transformation
formula d' = d/{1/[1(v^{2}/c^{2})]^{0.5}}.

Of course d'
cannot be
greater than or equal to d, but must be
less, because (v^{2}/c^{2})
must be a positive number, and so [1(v^{2}/c^{2})]
must
be less than 1, so the square root of [1(v^{2}/c^{2})]
must also be less than 1, which means that
{1/[1(v^{2}/c^{2})]^{0.5}}
must
be greater than 1.

Under these
conditions, however,
the length D of the mothership cannot
have changed from what it
was when the mothership and runabout were
clamped to each other, as was
the case in 1. above.

So in 5. and
6. above, the ratio
d'/D
cannot be 1/10 or 0.1, but must be
less, because d/D
= 1/10, and d' < d.

Let the
runabout now turn around,
return to the mothership and be clamped back onto
its hull. The ratio
between the lengths of the two is once again 1/10.

Now let the
clamps be released
a second time, but instead of the
runabout firing its engines,
let's say the mothership fires its
engines and it moves
away in a straight line from the runabout,
eventually reaching a constant
rectilinear velocity of v relative to the
runabout.

Under these
condition, the length
of the mother ship will now have contracted to D',
and according
to the Lorentz transformation formula, D' =
D/{1/[1(v^{2}/c^{2})]^{0.5}}.

And D'
cannot be greater
than or equal to D, but must be less,
because (v^{2}/c^{2})
must be a positive number, and so [1(v^{2}/c^{2})]
must
be less than 1, so the square root of [1(v^{2}/c^{2})]
must also be less than 1, which means that
{1/[1(v^{2}/c^{2})]^{0.5}}
must
be greater than 1.

Under these
conditions, however,
the length d of the runabout cannot
have changed from what
it was when the mothership and runabout were
clamped to each other, as
in 9. above (and in 1. above also.)

So now in 11.
and 12. above, the
ratio d'/D cannot be 1/10 or 0.1,
but must be more,
because d/D = 1/10, and D' < D.

But,
and this is a B
I G "but", according to the Theory of
Relativity, there should
be no difference whatsoever between 5. and
6. above on the one hand,
and 11. and 12. above on the other: because the
relative velocity between
mothership and runabout is exactly v in
all these cases!

This is
contradicted by the fact
that the results of the relative lengths of the
mothership and runabout
in 8. and 14. above are different from one
another.

And this in
turn proves that results
obtained by using the Lorentz transformation
equations  which are absolutely
essential for the Special Theory of Relativity 
contradict the Special
Theory of Relativity itself … proving that the
Special Theory of Relativity
must be mathematically selfcontradictory.
P.S.:
It should
be noted that it is impossible for the length of the
mothership to have
contracted in 7. compared to what it was in 1., nor
is it possible
for the length of the runabout to have contracted in
13. compared to what
it was in 9. That's because in both 1, and 7.
above, absolutely
nothing
happens
to the mothership; nor does anything happen to the
runabout in 9. and
13. above. The only thing that happens in 7. above is
that the runabout
changes its own relative velocity compared to
the mothership from
what it was in 1.  namely zero  to
v; and the only thing that
happens in 13. above is that the mothership
changes its
own
relative velocity compared to the runabout from
what it was in 1.
 namely zero  to v.
Any comments?
email
me.
